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2^(n-5)*6^(2n-4)=1/12^4*2
We move all terms to the left:
2^(n-5)*6^(2n-4)-(1/12^4*2)=0
We get rid of parentheses
2^(n-5)*6^(2n-4)-1/12^4*2=0
We multiply all the terms by the denominator
(2^(n-5)*6^(2n-4))*12^4*2-1=0
We move all terms containing n to the left, all other terms to the right
(2^(n-5)*6^(2n-4))*12^4*2=1
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